Fieldbus System Add 47 mm for each additional I/O Unit s. m is number of I/O Units.
P.50 34 No.JXC-OMU0004-A 7.3 SW (A) (B) PLC PLC SW (C) A,B,C A B C I/O I/O I/O 35 No.JXC-OMU0004-A A e i j PLC h 15 8.1 P.40 8.4 P.43 36 No.JXC-OMU0004-A B PLC I/O PLC PLC PLC PLC 3 i j 3 PLC PLC PLC PLC I/O g 7 LED f L L (1) 7 LED f (2) (3) 3 k n c 37 No.JXC-OMU0004-A C h [15] g 2 i j i h j g i 2 j i i h [0] j j 3 g 3 i OFF j 3 2 e h 0 h i g 3 j
(c) When switching from serial operation mode to parallel I/O operation mode, the currently active parallel I/O signals will be disabled. When switching to operation by parallel I/O signals, turn off all the parallel I/O signals and input them again after changing to the parallel I/O operation mode.
r t s i D l i O l e d o M s t e l t u o l i o f o r e b m u N k r a m e R 4 A V 4 s d n e h t o B 6 A V 6 s d n e h t o B Dimensions/Auto feed tank 0 1 A V 0 1 s d n e h t o B 6 1 A V 6 1 s d n e h t o B 4 B V 4 e d i s e n O 6 B V 6 e d i s e n O 8 B V 8 e d i s e n O s n o i t a c i f i c e p S h c t i w S t a o l F n o i t p i r c s e D 2 ~ 1 0 1 4 S I y t i c a p a C W 5 1 : C D , A V
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I/O size of port 1 and 2: 16 byte/16 byte for each I/O size of port 3 and 4: 2 byte/2 byte for each Unit 16/16/2/2 byte I/O size of port 1: 32 byte/32 byte each I/O size of port 2 to 4: 2 byte/2 byte for each 32/2/2/2 byte direct Data order is not swapped.
i i-1 () 3 i 1 1 3 IDF Series i-1 i-1 IDX-OM-W011 i i-2 5 i 2 1 IDF Series i-2 i-2 IDX-OM-W011 i i 2 2 i 2 3 50 i 2 4 i 2 5 0 IDF Series i-2 i-3 IDX-OM-W011 i i 2 6 WARNING !
Flange bracket material: Carbon steel 7-6-19 20 Series CQ2 Accessory Bracket Double Knuckle Joint Single Knuckle Joint For I-G012, I-Z015A I-G02, I-G03 For I-G04, I-G05 I-G08, I-G10 For Y-G012, Y-Z015A Y-G02, Y-G03 For Y-G04, Y-G05 Y-G08, Y-G10 ND hole H10 Axis d9 ND hole H10 Axis d9 Material: Carbon steel Material: Cast iron Material: Carbon steel Material: Cast iron NDH10 NX Applicable
I = I + I kgm m, m: Mass of loads I and I kg r, r: Diameters of loads I and I m L: Distance from the rotational axis to load I center of gravity m Calculation example When m 2.5kg, m = 0.5kg, r = 0.1m, r = 0.02m, L = 0.08m I = 2.5 x = 1.25 x 102 0.1 kgm 2 0.02 I = 0.5 x + 0.5 x 0.08 = 0.33 x 10kgm I = (1.25 + 0.33) x 10= 1.58 x 10kgm 16 Technical Data/Moment of Inertia Specific Application
1 i q !4 r e !0 !1 q i !2 o !3 y Component Parts No.