IR20-OM00008 (B),2 (C),(B)(A), () (B)(C) (A) BLEED (B) (C) OUT SUP SUP. 1 1 M Pa/ m ( B) m 2 N / m m m M Pa M Pa/ m m M Pa B m /N (A) ) ( N N m / N ( C) m 2 N ( A) m 2 N -5- 3. 1 SUP OUT 2 %F.S 3 4 R B(P36202028) G 2 3 Rc,F N IR2000G43-2-01 G43-P2-N01-X30 IR2010G43-4-01 G43-P4-N01-X30 IR2020G43-10-01 G43-P10-N01-X30 021/44 Rc NNPT FG 00.0050.2MPa 1: 0.010.4MPa 20.010.8MPa
/O.D. mm 5/8 6/9 6.5/10 8/12 8.5/12.5 Symbol 01 02 03 04 Symbol 50 60 65 80 85 15-2-87 16 16 Series KKH Dimensions: Socket (S) Male thread type (mm) A1 A2 When connected T Connection port size D H Width across flats L2 When connected Effective area mm2 L1 Min. bore size Body size Weight g A2 Model A1 T KKH3S-01MS R 1/8 33.5 20.4 20.4 6.0 36.0 14 40.0 37.5 D -02MS 19.6 R 1/4 1/8 31.5 19.5
Cycle time: T can be found from the following equation. Calculation example) T1 to T4 can be calculated as follows. L Speed: V [mm/s] a1 a2 T1 = V/a1 = 300/3000 = 0.1 [s], T3 = V/a2 = 300/3000 = 0.1 [s] Time [s] T = T1 + T2 + T3 + T4 [s] L 0.5 V (T1 + T3) V T1: Acceleration time and T3: Deceleration time can be obtained by the following equation.
= Tf x 1.5 Note 1) Necessary torque: T = Ta x 1.5 Note 1) Necessary torque: T = Ts Resistance load: Gravity or friction force is applied to rotating direction.
Time [s] LEC SS-T T1 T2 T3 T4 T1 = V/a1 [s] T3 = V/a2 [s] LEC Y T2: Constant speed time can be found from the following equation.
Lead 5: LES16K 3 Work load [kg] T1 = V/a1 = 220/5000 = 0.04 [s], Lead 10: LES16J 2 T3 = V/a2 = 220/5000 = 0.04 [s] T = T1 + T2 + T3 + T4 [s] T2 = L 0.5 V (T1 + T3) V T1: Acceleration time and T3: Deceleration time can be obtained by the following equation. 1 0 = 50 0.5 220 (0.04 + 0.04) 220 0 100 200 300 400 500 T1 = V/a1 [s] T3 = V/a2 [s] Speed [mm/s] = 0.19 [s]
2 t r @2 @1 #3 #4 #1 @9 #2 @5 @7 @4 @6 CY1H10 CY1H10-B CY1H10-BS CY1H10@3 @8 #0 t Material Note Component Parts No. 1 2 3 4 No.
How to Order S 2 B P H S4 200 LEY 63 A2 w y !0 i o e r t q u !1 !2 !3 !
9 y t @0 u Lead wire color Terminal no.
8 w $4 t e $2 !5 $3 y!7 @8 !4 !
Static load (Ts) When the resistance load is rotated, the Inertial load: Ta Ta = )W required torque calculated from the inertial load must be added. 2Q W = [rad/s2] Required torque T = Tf x (3 to 5) + Ta x 10 t2 Required torque: T = Ts Required torque: T T = Ta x 10 Resistance load (Tf) 2 x P Required torque: T = Tf x (3 to 5) = 0.000315 x x 10 = 0.055 [Nm] 0.62 Inertial load (Ta) 0.055
2 @1 @3 e u o t @2 !8 @0 @0 !2 !9 e @0 @1 o t u !8 @0 @2 !1 !4 @3 w i !5 y q r q w r y !5 !
(for std model) T XC30 Standard model no.
J, X, Z S, Y K, T J, X, Z Y K Z J J, T X S S, Y J, K, T X, Z J, K, T J, K, T S, Y J, K, T X, Z XA40 50, 63, 80, 100 XA41 XA42 XA43 50, 63, 80, 100 XA44 XA50 XA53 XA56 XA57 XA58 XA59 XA60 Change of double shaft length (Both sides with four chamfers) Axial: Bottom (Short shaft side) Change of double shaft length (With four chamfers, without keyway) Description Shaft type Applicable size
2 @1 @3 e u o t @2 !8 @0 @0 @3 !2 !9 e @0 @1 o t u !8 @0 @2 !1 !4 q w r y !5 !6 i w i !
A2 AK ASS T T ASR ASF Model T H D1 D2 D3 L1 L2 L6 A2 M L5 A1 Weight (g) Note 5) MAX.
A2 AK ASS T T ASR ASF Model T H D1 D2 D3 L1 L2 L6 A2 M L5 A1 Weight (g) Note 5) MAX.
L Speed: V [mm/s] Cycle time: T can be found from the following equation. a1 a2 T = T1 + T2 + T3 + T4 [s] T1: Acceleration time and T3: Deceleration time can be found by the following equation. Time [s] T1 T2 T3 T4 T1 = V/a1 [s] T3 = V/a2 [s] T2: Constant speed time can be found from the following equation.
Cycle time: T can be found from the following equation. L Speed:V [mm/s] Calculation example) T1 to T4 can be calculated as follows. a1 a2 T = T1 + T2 + T3 + T4 [s] Time [s] T1 = V/a1 = 300/3000 = 0.1 [s], T3 = V/a2 = 300/3000 = 0.1 [s] P T1: Acceleration time and T3: Deceleration time can be obtained by the following equation.