REA/REB

Static moment M2 = WL1 = 100.2 = 2 [Nm] 2 = M2/M2 max = 2/16 = 0.125 W = 1 [kg] = 10 [N] W Review M2. Since M1 & M3 are not generated, review is unnecessary. M L1 3. Dynamic moment We = 5 x 10-3WgU = 5 x 10-319.8300 = 15 [N ] Me3 = 1/3We(L2-A) = 1/3150.182 = 0.91 [Nm] 3 = Me3/Me3max = 0.91/10 = 0.091 Me3 Guide central axis We W L2 Review Me3.

Table of Contents

CX Dimensions Dimensions DM5 x 0.8 Relief port (Vacuum port) -X 20Data FB B + Stroke A + Stroke 5 10 FB B + Stroke A B Bore size (mm) FB A + Stroke 50 stroke or less 66 67.5 109 109 117.5 117.5 121 141 51 stroke or more 97.5 99 114 114 129 129 148 166 20 25 32 40 50 63 80 100 19 20 22 22 23 23 24 29 Other dimensions are the same as standard type. 66 67.5 71.5 78 83 88 102.5 120 A Over 30

REA/REB

moment M2 = WL (mm) Model REAH10 REAH15 REAH20 REAH25 REAHT25 REAHT32 A 15 17.5 19.5 23.5 L L A L M2 0 M1 0 M3 Since there are 2 guides, the guides central axis and the cylinders central axis are the same.

REA/REB

Static moment M2 = WL1 = 10 x 0.2 = 2 [Nm] 2 = M2/M2max = 2/16 = 0.125 W = 1 [kg] = 10 [N] W C J G5-S Examine M2. Since M1 & M3 are not generated, investigation is unnecessary. M CV MVGQ L1 CC We = 5 x 103 WgU = 5 x 103 x 1 x 9.8 x 300 = 15 [N] Me3 = 1/3We (L2A) = 1/3 x 15 x 0.182 = 0.91 [Nm] 3 = Me3/Me3max = 0.91/10 = 0.091 3.

17

m2 M3 m3 1.

Rotary Table Rack & Pinion Style Series MSQ Size: 1, 2, 3, 7, 10, 20, 30, 50, 70, 100, 200 1

Find the inertial moment B for the rotation of shaft (B). 3 + m2 a22 + K (Example) When shape of m2 is a sphere, refer to 7, and K = m2 2r2 2.

Rotary Table/

Find the inertial moment B for the rotation of shaft (B). 3 + m2 a22 + K (Example) When shape of m2 is a sphere, refer to 7, and K = m2 2r2 2.

CY1

Static moment M2 = WL1 = 100.05 = 0.5 [Nm] 2 = M2/M2max = 0.5/16 = 0.031 W = 1 [kg] =10 [N] Investigate M2. Since M1 & M3 are not generated, investigation is unnecessary. Find the value of M2max when Va = 300mm/s from . W M L1 From V = 1.4Va We = WV = 4/100101.4300 = 168 [N] Me3 = 1/3We(L2-A) = 1/31680.032 = 1.8 [Nm] 3 = Me3/Me3max = 1.8/7.2 = 0.250 3.

Battery-less

Then, replace the moment of inertia IB around the shaft (A) by IA, m2 + m2a22 + K 3 a12 I = m1 m1 (Ex.) Refer to 7 when the shape of m2 is spherical. b a IA = ( ) 2IB 5 2r2 Number of teeth = b K = m2 Load Type Load type Static load: Ts Resistance load: Tf Inertial load: Ta Only pressing force is necessary. (e.g. for clamping) Gravity or friction force is applied to rotating direction.

Magnetically Coupled Rodless Cylinder Series CY3 B R /CY1 1

0.5 70 100 300 500 1000 70 100 300 500 1000 Piston speed (mm/s) Piston speed (mm/s) M1 M2 Graph (3) Graph (2) Static Moment Moment generated by the workpiece weight even when the cylinder is stopped Pitch moment M1 = W L Yaw moment M3 = W (L A) Roll moment M2 = W L (mm) Model CY1H10 CY1H15 CY1H20 CY1H25 CY1HT25 CY1HT32 A 15 17.5 19.5 23.5 0 L L A L M2 M1 0 M3 Since there are 2 guides

Escapements Series MIW/MIS ø8, ø12, ø20, ø25, ø32 1

RHC FB MK(2) RS Q G With scraper With adjuster RS H A Hexagon width across flats RB RZQ RA Stroke adjuster MI W S SA CEP1 Hexagon width across flats RC CE1 RD SB SC RE CE2 Arrangement range RF mm Note) Observe the specified adjustment range when adjusting with a stroke adjuster.

Escapements Series MIW/MIS ø8, ø12, ø20, ø25, ø32 1

RHC FB MK(2) RS Q G With scraper With adjuster RS H A Hexagon width across flats RB RZQ RA Stroke adjuster MI W S SA CEP1 Hexagon width across flats RC CE1 RD SB SC RE CE2 Arrangement range RF mm Note) Observe the specified adjustment range when adjusting with a stroke adjuster.

KJ

M2 8 4.2 Applicable tubing L2 M2 L2 Different Diameter Tee: KQ2T Applicable tubing Applicable tubing O.D.

Air Fittings & Tubing

(mm) Effective area (mm2) Weight (g) M2 Part No.

V100

VS VQZ100 0.45 to 0.55 VQZ100-FB Series VQZ200 0.25 to 0.35 VQZ200-FB VFN 0 VQZ300 VQZ100 0.25 to 0.35 VQZ300-FB 1 VQZ200/300 Note) Tightening torque for mounting brackets on the valve.

Slider Type/Ball Bushing Bearing

L2 L1 xStatic moment Examine M2. Since M1 & M3 are not generated, investigation is unnecessary. M2 = W L1 = 10 0.05 = 0.5 [Nm] 2 = M2/M2 max = 0.5/16 = 0.031 W = 1 [kg] = 10 [N] W M Find the value M2 max when Va = 300 mm/s from Graph (3).

KJ

(inch) Note) Weight (g) 3-Applicable tubing M1 M2 D L1 L2 P Q Model KJU01-00 KJU03-00 KJU07-00 1 8 28.5 27.9 12.9 12.9 7.6 12.7 12.7 2.6 3 5 8.4 9.3 12 19 18.3 22.7 8.4 9.3 12 5.8 6.3 5 32 1 4 13.6 Note) D: Max. diameter 13.8 32.3 K M H Different Diameter. Union Y: KJU D Applicable tubing O.D.

ML2B

(Nm) ML2B/M1 (Pitch moment) ML2B/M2 (Roll moment) ML2B/M3 (Yaw moment) Pitch moment M1/M1e 10 20 40 Roll moment M2 1.2 2.4 4.8 Yaw moment M3/M3e 3.0 6.0 12 MI W S 40 Model 20 30 YES 20 5 4 3 10 ML2B25 ML2B32 ML2B40 CEP1 If speed or load changes, stopping time may vary and positioning accuracy may be compromised.

ML2B

(Nm) ML2B/M1 (Pitch moment) ML2B/M2 (Roll moment) ML2B/M3 (Yaw moment) Pitch moment M1/M1e 10 20 40 Roll moment M2 1.2 2.4 4.8 Yaw moment M3/M3e 3.0 6.0 12 MI W S 40 Model 20 30 YES 20 5 4 3 10 ML2B25 ML2B32 ML2B40 CEP1 If speed or load changes, stopping time may vary and positioning accuracy may be compromised.

Transfer

Pitch moment Roll moment NO NO M1 = W1 x L1 M2 = W3 x L3 L1 L3 YES The product is operatable at 14.5 mT or less magnetic field ? Is there any influence from magnetic fields ? (Refer to Caution on Handling on pages 706 and 707.) M1 M2 YES W1 NO W3 NO M1 = W4 x L3 M2 = W1 x L2 Do not use it since it will result in a miscount. L3 L2 YES Is water, oil, burr or dust present?