HRL Q = qm x C x (T2 T1) x qv x C x iT 60 1 x 70 x 4.186 x 103 x 4.0 60 = = qm x C x (T2 T1) 860 Q = = 19535 [J/s] 19535 [W] = 19.5 [kW] x qv x 60 x C x iT 860 = Cooling capacity = Considering a safety factor of 20%, 19.5 [kW] x 1.2 = 23.4 [kW] 1 x 70 x 60 x 1.0 x 103 x 4.0 860 = Thermo-chiller T1: Outlet temperature Q: Heat generation amount 1680 [cal/h] 860 Users equipment = T = T2 T1
Power supply 11) 100/110V AC (50/60Hz) 200/220V AC (50/60Hz) 21) 1) Consult SMC if the supply voltage for LC1-1HV1 will be 110V AC or more, or the supply voltage for LC1-1HV2 will be 220V AC or more. or LC1-1-T1(Teaching box) are required.
L1 Low noise nozzle with male thread/KNS (mm) Model Nozzle size D Connection size L1 A Width across flats H1 0.75 x 4 1 x 4 0.9 x 8 0.75 x 4 0.9 x 8 1 x 4 1.1 x 8 R 1/8 R 1/8 R 1/8 R 1/4 R 1/4 R 1/4 R 1/4 12 12 12 14 14 14 14 18 18 18 20 20 20 20 14 14 14 14 14 14 14 KNS-R01-075-4 KNS-R01-100-4 KNS-R01-090-8 KNS-R02-075-4 KNS-R02-090-8 KNS-R02-100-4 KNS-R02-110-8 D 2 H1 A L1 Connection
L D d m t d H B C l IY-G04 IY-G05 C type 10 for shaft 41.6 50.6 9.6 13.4 36.2 44.2 1.55 2.05 1.15 1.15 M14 x 1.5 M18 x 1.5 8 11 22 27 25.4 31.2 C type 14 for shaft 10 14 -0.040 -0.076 -0.050 -0.093 9-12-19 20 Simple Joint: 32 to 63 Type A Mounting Bracket 2-D T1 T2 M W V U F B E (mm) Joint and Mounting Bracket (Type A, Type B) Part No.
[W] = 7.3 [kW] T = T2 T1 Cooling capacity = Considering a safety factor of 20%, 7.3 [kW] x 1.2 = 8.8 [kW] T1: Outlet temperature 23 Cooing Capacity Calculation Series HRS100/150 Required Cooling Capacity Calculation Example 3: When there is no heat generation, and when cooling the object below a certain temperature and period of time.
L D d m t d H B C C type 10 for shaft 41.6 50.6 9.6 13.4 36.2 44.2 1.55 2.05 1.15 1.15 M14 x 1.5 M18 x 1.5 8 11 22 27 25.4 31.2 IY-G04 IY-G05 C type 14 for shaft 10 14 -0.040 -0.076 -0.050 -0.093 14 Series RLQ Simple Joint/32 to 63 A type mounting bracket 2-D T1 T2 M W V U F B E (mm) Joint and mounting bracket (A type, B type) part no.
[W] = 7.3 [kW] T = T2 T1 Cooling capacity = Considering a safety factor of 20%, 7.3 [kW] x 1.2 = 8.8 [kW] T1: Outlet temperature 118 Cooling Capacity Calculation HRS100/150 Series Required Cooling Capacity Calculation Example 3: When there is no heat generation, and when cooling the object below a certain temperature and period of time.
flats 14 25 2.5 25 2.5 2 2 Dimensions Dimensions Part no.
1 0 115.2kbps B RATE 1(LEC-T1)IF115.2kbps 2 4.2(CN2SW) TM (CN2SW) Deviceet TM(CN2SW) Deviceet () PC/TB(CN2)(LEC-T1-)(LEC-W2)(LEC) TM(LEC) (CN2SW)Deviceet 15 - 4.3(LEC) (LEC)(LEC-T1-) (LEC-W2)(LEC) (LEC)(LEC)(LEC-T1-) 4.3.1 ID 2(LEC)ID (LEC)IDID112 ID (LEC-W2) Normal Parameter Controller ID () Download (IDID ) 4.3.2 IF(LEC)(LEC-T1) IF115.2kbps (LEC-W2) Normal HELP-Password 16 - Para
, 15 Straights and Straight Manifolds . . . . . 14 Elbows and 45 Elbows . . . . . . . . . . . . 14 Tees . . . . . . . . . . . . . . . . . . . . . . . . . . . 15 Combo Tees (3 branches) . . . . . . . . . . 15 L-Tees and V-Tees . . . . . . . . . . . . . . . . 15 1/4 Female pipe thread-to-tube . . . . . 16, 17 Straights and Straight Manifolds . . . . . 16 Elbows . . . . . . . . . . . . . . .
-25 NPN output NPN open collector 30V, 80mA, residual voltage: 1V or less ZSE401 T1-26 Vacuum Analog output 1~5V (+ 5%F.S.), load impedance : 1k ZSE401 T1-65 PNP output PNP open collector 80mA ISE4L01 T1-25 Positive Pressure NPN output NPN open collector 30V, 80mA, residual voltage: 1V or less ISE4L01 T1-26 100kPa Analog output 1~5V (+ 5%F.S.), load impedance: 1k ISE4L01 T1-65 (14.5PSI) Type
response Start ID Note 2) Error function Check Details of sum End code error ) T1-T2-T3-T4 1 byte 1 byte 1 byte 2 bytes T1-T2-T3-T4 The MSB of the function code is Problems 3.5 character code Note 5) CRC 3.5 character times Note 1) 01 FF times Note 1) changed to 1.
14 Circulating fluid pressure [MPa] Circulating fluid pressure [MPa] Outlet: 60 Hz Outlet: 60 Hz 0.12 0.12 12 12 0.10 0.10 Pump head [m] Pump head [m] 10 10 0.08 0.08 8 8 Outlet: 50 Hz Outlet: 50 Hz 0.06 0.06 6 6 0.04 0.04 4 4 Allowable operating range Allowable operating range Return port Return port 0.02 0.02 2 2 0.00 0.00 0 2 4 6 8 10 12 14 16 0 2 4 6 8 10 12 14 16 Circulating fluid flow
Connector C Actuator side (Terminal no.) 1 2 5 6 (14) (18) 8 A1 B1 (13.5) (17.7) (17.7) Cable length (L) 1 3 5 8 A B C 1 2 A6 B6 1.5 m 3 m 5 m 8 m (30.7) Connector A 5 6 (14.7) Connector D L (11) (10) 8 A B C LE-CP/Cable length: 8 m, 10 m, 15 m, 20 m ( Produced upon receipt of order) Controller side 10 m (14.2) Connector C (Terminal no.) 1 2 5 6 15 m 5.5 6.3 Actuator side (14) (18) (Terminal
E@-M3 inch(mm) $ f grf r, i -, :,,1 i ,t1':-/,r:frt crommet(G).
E@-M3 inch(mm) $ f grf r, i -, :,,1 i ,t1':-/,r:frt crommet(G).
E@-M3 inch(mm) $ f grf r, i -, :,,1 i ,t1':-/,r:frt crommet(G).
JXC-OMT0034CN (GW)(CC-Link) / LEC-GMJ2 1. . 4 2. . 6 2.1 . 6 2.2 . 6 2.3 . 7 2.4 () . 8 (1) . 8 (2). 8 (3)(LEC) . 8 (4). 8 (5) . 8 (6) . 9 (7) . 9 3. . 10 3.1 . 10 3.2 . 12 3.3 . 13 (1)(LECGMJ2) . 13 (2)DIN (LECGMJ2D) . 13 3.4 . 14 (1) . 14 (2) . 14 4. . 15 4.1 (STATION NO.,B RATE) . 15 4.2 (CN2SW) . 16 4.3 (LEC) . 17 5. . 19 5.1 CN4 . 19 5.2 CN3 . 19 5.3 CN1CONT . 19 5.4 CN2PC
Q = qm x C x (T2 T1) x qv x C x iT 60 1 x 35 x 4.186 x 103 x 3.0 60 = = qm x C x (T2 T1) 860 Q = = 7325 [J/s] 7325 [W] = 7.3 [kW] x qv x 60 x C x iT 860 = Cooling capacity = Considering a safety factor of 20%, 7.3 [kW] x 1.2 = 8.8 [kW] 1 x 35 x 60 x 1.0 x 103 x 3.0 860 = Q: Heat generation T1: Outlet Thermo-chiller temperature amount Customer equipment T = T2 T1 7325 [W] = 7.3 [kW]
Time [s] Method 2: Calculation T1 T2 T3 T4 T5 T6 Cycle time T can be found from the following equation. L : Stroke [mm] V : Speed [mm/s] a1: Acceleration [mm/s2] a2: Deceleration [mm/s2] T = T1 + T2 + T3 + T4 [s] Calculation example) T1 to T4 can be calculated as follows. T1 and T3 can be obtained by the following equation.