SMC Corporation of America
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Search Results "ZA1051-J16LB-B-M1"

A part z1 m1 = 40 X 7 X 8 X 2.7 X 10-6 Calculation of weight m1 = a X b X c X Specific gravity = 0.006(kg) Iz1 = {0.006 X (40 2+7 2)/12} X 10-6 Moment of inertia around Z1 axis = 0.8 X 10-6 (kgm 2) = 0.8 X 10-6+ 0.006 X 37 2 X 10-6 Iz1 = {m1(a 2+ b 2)/12} X 10-6 IA = 9.0 X 10-6(kgm 2) Moment of inertia around Z axis IA = IZ1 + m1r1 2 X 10-6 z r2 Z2 B part r2 = 47(mm) m2 = 5 X 10 X 12 X

depth 6.2 PF2M711/721-F2(-L) 78 21 2.8 depth 6.2 PF2MmL-m1/2(-L) 48 A 18 OUT1 OUT2 10.2 DC() DC(+) 1.4 38.5 (30.9) 3 C 18 2 x 3.4 Width across flats B OUT IN 68 2 x Port size Port size: 1, 2 [mm] 28 Model A C B P PF2M701/702/705/710/ 725/750L-01(-L) 84.4 11 14 2.8 depth 8.4 8 PF2M701/702/705/710/ 725/750L-N1(-L) 84.4 12 14 2.8 depth 8.4 2 x P PF2M701/702/705/710/ 725/750L-F1(-L) 84.4 13

Calculate the moment of inertia of attachment. z r1 Material of attachment: Aluminum alloy (Specific gravity = 37 (mm) r2 = 2.7) A part z1 m1 = 40 x 7 x 8 x 2.7 x 10-6 = 0.006 (kg) Calculation of weight m1 = a x b x c x Specific gravity Moment of inertia around Z1 axis IZ1 = {m1(a2 + b2)/12} X 10-6 Iz1 = {0.006 x (402 + 72)/12} x 10-6 = 0.8 x 10-6 (kgm2) IA = 0.8 x 10-6 + 0.006 x 372 x 10

Applicable bore Shock absorber model ML1-A25H ML1-A32H ML1-A40H ML1C25 ML1C32 ML1C40 101 90 25 20 11 72 67.3 12 31 39.5 Max. 16.5 4.5 3 RB1412 120 107 30 25 16 93 73.2 15 38 49 Max. 20 5.5 6 RB2015 147 129 30 31 16 105.5 73.2 15 40.5 54.5 Max. 25 5.5 6 Side Support Side support A 2 x G E E F 2 x H A B Side support B 2 x J A B (mm) A B C D E F G H J Part no.

Calculate the moment of inertia of attachment. z r1 Material of attachment: Aluminum alloy (Specific gravity = 37 (mm) r2 = 2.7) A part z1 m1 = 40 x 7 x 8 x 2.7 x 10-6 = 0.006 (kg) Calculation of weight m1 = a x b x c x Specific gravity Moment of inertia around Z1 axis IZ1 = {m1(a2 + b2)/12} X 10-6 Iz1 = {0.006 x (402 + 72)/12} x 10-6 = 0.8 x 10-6 (kgm2) IA = 0.8 x 10-6 + 0.006 x 372 x 10

Actuating port Left A B C Actuating port Right Brake release port 9-14-1 2 Before Operation Maximum Allowable Moment/Maximum Load Weight Maximum Allowable Moment Allowable moment (Nm) Maximum load weight (kg) Model W4 W3 W2 M2 M3 W1 M1 Select the moment within the limits shown in the graphs below.

A part z1 m1 = 20 x 3 x 4 x 2.7 x 10-6 = 6.48 x 10-4 (kg) Weight calculation m1 = a x b x c x Relative density IZ1 Inertial moment around Z1 axis IZ1 = {m1 (a2 + b2) / 12} x 10-6 = {6.48 x 10-4 x (202 + 32)/12} x 10-6 = 2.21 x 10-8 (kg.m2) = 2.21 x 10-8 + 6.48 x 10-4 x 16.42 x 10-6 = 0.20 x 10-6 (kg.m2) IA Inertial moment around Z axis IA =IZ1 + m1r12 x 10-6 z f2 z2 B part r2 = 23.5(mm)

Actuating port Left A B C Actuating port Right Brake release port 9-14-1 2 Before Operation Maximum Allowable Moment/Maximum Load Weight Maximum Allowable Moment Allowable moment (Nm) Maximum load weight (kg) Model W4 W3 W2 M2 M3 W1 M1 Select the moment within the limits shown in the graphs below.

A part z1 m1 = 20 x 3 x 4 x 2.7 x 10-6 = 6.48 x 10-4 (kg) Weight calculation m1 = a x b x c x Relative density IZ1 Inertial moment around Z1 axis IZ1 = {m1 (a2 + b2) / 12} x 10-6 = {6.48 x 10-4 x (202 + 32)/12} x 10-6 = 2.21 x 10-8 (kg.m2) = 2.21 x 10-8 + 6.48 x 10-4 x 16.42 x 10-6 = 0.20 x 10-6 (kg.m2) IA Inertial moment around Z axis IA =IZ1 + m1r12 x 10-6 z f2 z2 B part r2 = 23.5(mm)

Calculate the moment of inertia of attachment. z r1 Material of attachment: Aluminum alloy (Specific gravity = 2.7) A part z1 r1 = 37 (mm) Calculation of weight m1 = a x b x c x Specific gravity m1 = 40 x 7 x 8 x 2.7 x 10-6 = 0.006 (kg) Moment of inertia around Z1 axis IZ1 = {m1(a2 + b2)/12} x 10-6 Iz1 = {0.006 x (402 + 72)/12} x 10-6 = 0.8 x 10-6 (kgm2) IA = 0.8 x 10-6 + 0.006 x 372 x 10

A part z1 m1 = 20 x 3 x 4 x 2.7 x 10-6 = 6.48 x 10-4 (kg) Weight calculation m1 = a x b x c x Relative density IZ1 Inertial moment around Z1 axis IZ1 = {m1 (a2 + b2) / 12} x 10-6 = {6.48 x 10-4 x (202 + 32)/12} x 10-6 = 2.21 x 10-8 (kg.m2) = 2.21 x 10-8 + 6.48 x 10-4 x 16.42 x 10-6 = 0.20 x 10-6 (kg.m2) IA Inertial moment around Z axis IA =IZ1 + m1r12 x 10-6 z f2 z2 B part r2 = 23.5(mm)

M1 Applicable tubing O.D.: 3.2, 4, 6 1/8", 5/32" 2 x Applicable tubing O.D. d Front view Right side view Metric Size Model Applicable tubing O.D. d D1 Release button D2 D3 D4 D5 L1 L2 L3 L41 L5 L6 L7 L8 M1 W1 W2 X1 X2 Weight [g] X(X) Y Max.

M1 Applicable tubing O.D.: 3.2, 4, 6 1/8", 5/32" Metric Size Model Applicable tubing O.D.d D1 Release button D2 D3 D4 D5 L1 L2 L3 L41 L5 L6 L7 L8 M1 Weight [g] X(X) Y Max.

Connection thread R Applicable tubing Bracket mounting dimensions B S (Width across flats) Weight (g) O. D.

B L1 H 1(P) 2(A) C D E F G J K L3 L4 L5 L6 Q L2 M1 Model 1(P)2(A) 29.1 53.9 24.3 29.6 52.9 23.8 15.8 16.8 11 2.0 1.2 19 49 11 21 50 13 M5 4 6 VHK-B1A 44.5 14.5 1 27 22 16.5 26 VHKl-M5-06F VHKl-M5-04F 18 41 16.5 3.5 3.4 1.2 21 51 11 23 53 13 4 6 VHK-B1A 44.5 14.5 1 27 22 16.5 26 VHKl-01S-06F VHKl-01S-04F 18 41 55.4 23.8 31.6 56.9 24.3 32.6 16.5 3.5 15.8 16.8 11 7.2 9.7 1 8 8 VHKl-01S-08F 62.2

Load at lever end DNumber of teeth = a 20= m1 a12 1. Find the inertial moment B for the rotation of shaft (B). 3 + m2 a22 + K (Example) When shape of m2 is a sphere, refer to 7, and K = m2 2r2 2.

0Gear transmission oLoad at lever end Number of teeth = a = m1 a12 1. Find the inertial moment B for the rotation of shaft (B). 3 + m2 a22 + K (Example) When shape of m2 is a sphere, refer to 7, and K = m2 2r2 2.

D-A7lH, A80H D-A73C, A80C D-F7l, J79 D-F7lV, J79C D-A79W D-F9l D-F9lV D-F9lWV D-F9lW D-F9BAL D-P5DW D-A9l D-A9lV D-A7, A8 Model B 6.5 7 6 8.5 11.5 14.5 A 28.5 29 33 24 28.5 28.5 B 7 7.5 6.5 9 12 15 B 4 4.5 3.5 6 9 12 B 11 11.5 10.5 13 16 19 B 4.5 7.5 10.5 B 5 7.5 10.5 13.5 B 9 11.5 14.5 17.5 A 34.5 25.5 30 30 B 8 10.5 13.5 16.5 A 19.5 24 24 A 28 28.5 32.5 23.5 28 28 A 25.5 26 30 21